Relation between the volume of gas (2) that dissolves in a fixed volume of solvent (1) and the partial pressure of gas (2) is ( n t =. total moles, K 1 and K 2 are Henry's constants)

Question

Relation between the volume of gas (2) that dissolves in a fixed volume of solvent (1) and the partial pressure of gas (2) is ( n t =. total moles, K 1 and K 2 are Henry's constants) (A) n 1 RT / n 2 (B) n 2 RT / K 2 p 2 (C) n t RT / K 2 (D) None of these

Tardigrade Admin · Accepted Answer

By Henry's law, p= chi K H For solute, p2= chi2 K 2 =(n2/n1+n2) K 2=(n2 K 2/n1) Also, p2=(n2 R T/V) ∴ (n2 R T/V)=(n2/n1) K 2 ∴ (R T/V)=( K 2/nt) ∴ V=(nt R T/ K 2)

Q. Relation between the volume of gas $(2)$ that dissolves in a fixed volume of solvent $(1)$ and the partial pressure of gas $(2)$ is $(n_{t} =$ total moles, $K_{1}$ and $K_{2}$ are Henry's constants)

$n_{1} RT / n_{2}$

$n_{2} RT / K_{2} p_{2}$

$n_{t} RT / K_{2}$

None of these

Q. Relation between the volume of gas (2) that dissolves in a fixed volume of solvent (1) and the partial pressure of gas (2) is (nt​= total moles, K1​ and K2​ are Henry's constants)

n1​RT/n2​

n2​RT/K2​p2​

nt​RT/K2​

None of these

By Henry's law, p=χKH​ For solute, p2​=χ2​K2​ =n1​+n2​n2​​K2​=n1​n2​K2​​ Also, p2​=Vn2​RT​ ∴Vn2​RT​=n1​n2​​K2​ ∴VRT​=nt​K2​​ ∴V=K2​nt​RT​

Q. Relation between the volume of gas $(2)$ that dissolves in a fixed volume of solvent $(1)$ and the partial pressure of gas $(2)$ is $(n_{t} =$ total moles, $K_{1}$ and $K_{2}$ are Henry's constants)

$n_{1} RT / n_{2}$

$n_{2} RT / K_{2} p_{2}$

$n_{t} RT / K_{2}$