Relation between permeability μ and magnetizing field H for a sample of iron is μ=((0.4/H)+12 × 10-4) henery/ metre, where unit of H is A / m. Find value of H( in A / m ) for which magnetic induction of 1.0 Wb / m 2 can be produced.

Question

Relation between permeability μ and magnetizing field H for a sample of iron is μ=((0.4/H)+12 × 10-4) henery/ metre, where unit of H is A / m. Find value of H( in A / m ) for which magnetic induction of 1.0 Wb / m 2 can be produced. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Magnetic induction, B=μ H (For medium) 1=((0.4/H)+12 × 10-4) H 1=0.4+12 × 10-4 H ⇒ H=(1-0.4/12 × 10-4)=500 A / m

Q. Relation between permeability $μ$ and magnetizing field $H$ for a sample of iron is $μ = (\frac{0.4}{H} + 12 \times 1 0^{- 4})$ henery/ metre, where unit of $H$ is $A / m$ . Find value of $H ($ in $A / m)$ for which magnetic induction of $1.0 Wb / m^{2}$ can be produced.

Magnetic induction, $B = μ H$ (For medium)
$1 = (\frac{0.4}{H} + 12 \times 1 0^{- 4}) H$
$1 = 0.4 + 12 \times 1 0^{- 4} H$
$\Rightarrow H = \frac{1 - 0.4}{12 \times 1 0 ^{- 4}} = 500 A / m$

Q. Relation between permeability μ and magnetizing field H for a sample of iron is μ=(H0.4​+12×10−4) henery/ metre, where unit of H is A/m. Find value of H( in A/m) for which magnetic induction of 1.0Wb/m2 can be produced.

Magnetic induction, B=μH (For medium) 1=(H0.4​+12×10−4)H 1=0.4+12×10−4H ⇒H=12×10−41−0.4​=500A/m

Q. Relation between permeability $μ$ and magnetizing field $H$ for a sample of iron is $μ = (\frac{0.4}{H} + 12 \times 1 0^{- 4})$ henery/ metre, where unit of $H$ is $A / m$ . Find value of $H ($ in $A / m)$ for which magnetic induction of $1.0 Wb / m^{2}$ can be produced.

Magnetic induction, $B = μ H$ (For medium)
$1 = (\frac{0.4}{H} + 12 \times 1 0^{- 4}) H$
$1 = 0.4 + 12 \times 1 0^{- 4} H$
$\Rightarrow H = \frac{1 - 0.4}{12 \times 1 0 ^{- 4}} = 500 A / m$