Reimer-Tiemann reaction introduces an aldehyde group, on to the aromatic ring of phenol, ortho to the hydroxyl group. This reaction involves electrophilic aromatic substitution. This is a general method for the synthesis of substituted salicylaldehydes as depicted below. Which one of the following reagents is used in the above reaction?

Question

Reimer-Tiemann reaction introduces an aldehyde group, on to the aromatic ring of phenol, ortho to the hydroxyl group. This reaction involves electrophilic aromatic substitution. This is a general method for the synthesis of substituted salicylaldehydes as depicted below. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b973dc2167e52ae5d92d4c0b6e037123-.png" /> Which one of the following reagents is used in the above reaction? (A) aq. NaOH + CH 3 Cl (B) aq. NaOH + CH 2 Cl 2 (C) aq. NaOH + CHCl 3 (D) aq. NaOH + CCl 4

Tardigrade Admin · Accepted Answer

The reactive intermediate (reagent) for the reaction is generated by the following reaction OH - text (aq.) + CHCl 3 leftharpoons CCl 3-+ H 2 O CCl 3- arrow Cl -: CCl 4

aq. $N a O H + C H_{3} Cl$

aq. $N a O H + C H_{2} C l_{2}$

aq. $N a O H + C H C l_{3}$

aq. $N a O H + CC l_{4}$

The reactive intermediate (reagent) for the reaction is generated by the following reaction
$O H^{-} (aq.) + C H C l_{3} ⇌ CC l_{3}^{-} + H_{2} O$
$CC l_{3}^{-} \to C l^{-} : CC l_{4}$

aq. NaOH+CH3​Cl

aq. NaOH+CH2​Cl2​

aq. NaOH+CHCl3​

aq. NaOH+CCl4​

The reactive intermediate (reagent) for the reaction is generated by the following reaction OH−(aq.) +CHCl3​⇌CCl3−​+H2​O CCl3−​→Cl−:CCl4​

aq. $N a O H + C H_{3} Cl$

aq. $N a O H + C H_{2} C l_{2}$

aq. $N a O H + C H C l_{3}$

aq. $N a O H + CC l_{4}$

The reactive intermediate (reagent) for the reaction is generated by the following reaction
$O H^{-} (aq.) + C H C l_{3} ⇌ CC l_{3}^{-} + H_{2} O$
$CC l_{3}^{-} \to C l^{-} : CC l_{4}$