Refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then,

Question

Refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then, (A)  D1 > D2  (B)  D1 < D2  (C)  D1 = D2  (D)  D1 can be less than or greater than depending upon angle of prism

Tardigrade Admin · Accepted Answer

The refractive index of a prism is given by

μ = \frac{s i n \frac{1}{2} ( A + D )}{s i n ( \frac{A}{D} )} ... (i)

where,

A =

angle of prism and

D =

angle of minimum deviation
It follows from Eq.

(i)

that greater the refractive index, the greater is the angle of minimum deviation. Since, the refractive index for the blue light greater than that of red light, the angle of minimum deviation (

D_{2}

) for blue light will be greater than that (i.e. angle

D_{1}

) for red light.

Q. Refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then,

$D_{1} > D_{2}$

$D_{1} < D_{2}$

$D_{1} = D_{2}$

$D_{1}$ can be less than or greater than depending upon angle of prism

Q. Refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1​ and D2​ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then,

D1​>D2​

D1​<D2​

D1​=D2​

D1​ can be less than or greater than depending upon angle of prism

Q. Refractive index of glass is $1.520$ for red light and $1.525$ for blue light. Let $D_{1}$ and $D_{2}$ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then,

$D_{1} > D_{2}$

$D_{1} < D_{2}$

$D_{1} = D_{2}$

$D_{1}$ can be less than or greater than depending upon angle of prism