Referring to the zener diode circuit shown in figure, if E =15 V , V z =9 V and R L =3.6 k Ω, then the power dissipated in R L is mW.

Question

Referring to the zener diode circuit shown in figure, if E =15 V , V z =9 V and R L =3.6 k Ω, then the power dissipated in R L is mW. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Current through R L , I L =( V z / R L )=(9/3.6 × 103) =2.5 × 10-3 A ∴ Power dissipated in R L P L = V z I L =9 × 2.5 × 10-3 =22.5 × 10-3 W ∴ P L =22.5 mW

Q. Referring to the zener diode circuit shown in figure, if $E = 15 V, V_{z} = 9 V$ and $R_{L} = 3.6 k Ω$ , then the power dissipated in $R_{L}$ is_______ $mW$ .

Current through $R_{L}$ ,
$I_{L} = \frac{V _{z}}{R _{L}} = \frac{9}{3.6 \times 1 0 ^{3}}$
$= 2.5 \times 1 0^{- 3} A$
$∴$ Power dissipated in $R_{L}$
$P_{L} = V_{z} I_{L} = 9 \times 2.5 \times 1 0^{- 3}$
$= 22.5 \times 1 0^{- 3} W$
$∴ P_{L} = 22.5 mW$

Q. Referring to the zener diode circuit shown in figure, if E=15V,Vz​=9V and RL​=3.6kΩ, then the power dissipated in RL​ is_______ mW.

Current through RL​, IL​=RL​Vz​​=3.6×1039​ =2.5×10−3A ∴ Power dissipated in RL​ PL​=Vz​IL​=9×2.5×10−3 =22.5×10−3W ∴PL​=22.5mW

Q. Referring to the zener diode circuit shown in figure, if $E = 15 V, V_{z} = 9 V$ and $R_{L} = 3.6 k Ω$ , then the power dissipated in $R_{L}$ is_______ $mW$ .

Current through $R_{L}$ ,
$I_{L} = \frac{V _{z}}{R _{L}} = \frac{9}{3.6 \times 1 0 ^{3}}$
$= 2.5 \times 1 0^{- 3} A$
$∴$ Power dissipated in $R_{L}$
$P_{L} = V_{z} I_{L} = 9 \times 2.5 \times 1 0^{- 3}$
$= 22.5 \times 1 0^{- 3} W$
$∴ P_{L} = 22.5 mW$