Question

Refer to the given reaction.
$2H_{2}O\to 4H^{+}+O_2+4e^{-}$
Where does this reaction take place in the chloroplasts of plants?

• A. Outer surface of thylakoid membrane
• B. Inner surface of thylakoid membrane
• C. In the matrix (stroma)
• D. Intermembrane space

Answer 1

Answer: (B)

The splitting of water is associated with the $PSII$. Water is split into $H^{+},[O]$ and electrons. The electrons needed to replace those removed from photosystem $I$ are provided by photosystem $II$.
$2H_{2}O\to 4H^{+}+O_2+4e^{-}$
Water splitting complex is associated with the PSII, which itself is physically located on the inner side of the membrane of the thylakoid. The liberation of $O_2$ during photolysis of water involves the role of $M{n}^{2+},C{a}^{2+}$ and $C{l}^{-}$ ions.