Rearrange the following (I to IV) in the order of in creasing masses and choose the correct answer from (a), (b), (c), (d). (atomic masses: N =14, O =16, Cu =63) I. 1 molecule of oxygen II. 1 atom of nitrogen III. 1 × 1010 g molecular weight of oxygen IV. 1 × 10-18 g atomic weight of copper

Question

Rearrange the following (I to IV) in the order of in creasing masses and choose the correct answer from (a), (b), (c), (d). (atomic masses: N =14, O =16, Cu =63) I. 1 molecule of oxygen II. 1 atom of nitrogen III. 1 × 1010 g molecular weight of oxygen IV. 1 × 10-18 g atomic weight of copper (A) II < I < IV < III (B) IV < III < II < I (C) II < III < I < IV (D) III < IV < I < II

Tardigrade Admin · Accepted Answer

(i) 1 Molecule of O 2=(32/6.023 × 1023) =0.5 × 10-23 gm (ii) 1 atom of N =(14/6.023 × 1023) =2.3 × 10-23 gm (iii) 10-10 gm mol wt. of oxygen =10-10 × 32=3.2 × 10-9 gm (iv) 10-10 gm atom of copper =10-10 × 63=6.3 × 10-9 gm

Q. Rearrange the following (I to IV) in the order of in creasing masses and choose the correct answer from (a), (b), (c), (d). (atomic masses: N=14,O=16,Cu=63) I. 1 molecule of oxygen II. 1 atom of nitrogen III. 1×1010g molecular weight of oxygen IV. 1×10−18g atomic weight of copper

II < I < IV < III

IV < III < II < I

II < III < I < IV

III < IV < I < II

(i) 1 Molecule of O2​=6.023×102332​ =0.5×10−23gm (ii) 1 atom of N=6.023×102314​ =2.3×10−23gm (iii) 10−10gmmol wt. of oxygen =10−10×32=3.2×10−9gm (iv) 10−10gm atom of copper =10−10×63=6.3×10−9gm