Reaction of propene with diborane followed alkaline hydrolysis in the presence of hydrogen peroxide gives

Question

Reaction of propene with diborane followed alkaline hydrolysis in the presence of hydrogen peroxide gives (A) 1-propanol (B) 2-propanol (C) 1, 2-dihydroxypropane (D) n-propane

Tardigrade Admin · Accepted Answer

CH 3- CH = CH 2+( H - BH 2)2 arrow CH 3- CH 2- CH 2 BH 2 xrightarrowCH3CH =CH2 ( CH 3- CH 2- CH 2)2 BH xrightarrow CH 3 CH = CH 2 ( CH 3 CH 2 CH 2)3 B xrightarrow[OH-] H 2 O , 3 H 2 O 2 underset text propan-1-ol 3 CH 3 CH 2 CH 2 OH + B ( OH )3

Q. Reaction of propene with diborane followed alkaline hydrolysis in the presence of hydrogen peroxide gives

1-propanol

2-propanol

1, 2-dihydroxypropane

n-propane

$C H_{3} - C H = C H_{2} + (H - B H_{2})_{2} \to C H_{3} - C H_{2} - C H_{2} B H_{2} C H_{3} C H = C H_{2}$
$(C H_{3} - C H_{2} - C H_{2})_{2} B H C H_{3} C H = C H_{2}$
$(C H_{3} C H_{2} C H_{2})_{3} B H_{2} O, 3 H_{2} O_{2} O H^{-}$
$propan-1-ol 3 C H_{3} C H_{2} C H_{2} O H + B (O H)_{3}$

Q. Reaction of propene with diborane followed alkaline hydrolysis in the presence of hydrogen peroxide gives

1-propanol

2-propanol

1, 2-dihydroxypropane

n-propane

CH3​−CH=CH2​+(H−BH2​)2​→CH3​−CH2​−CH2​BH2​CH3​CH=CH2​​ (CH3​−CH2​−CH2​)2​BHCH3​CH=CH2​​ (CH3​CH2​CH2​)3​BH2​O,3H2​O2​OH−​ propan-1-ol 3CH3​CH2​CH2​OH​+B(OH)3​

$C H_{3} - C H = C H_{2} + (H - B H_{2})_{2} \to C H_{3} - C H_{2} - C H_{2} B H_{2} C H_{3} C H = C H_{2}$
$(C H_{3} - C H_{2} - C H_{2})_{2} B H C H_{3} C H = C H_{2}$
$(C H_{3} C H_{2} C H_{2})_{3} B H_{2} O, 3 H_{2} O_{2} O H^{-}$
$propan-1-ol 3 C H_{3} C H_{2} C H_{2} O H + B (O H)_{3}$