Reaction of phenol with chloroform/sodium hydroxide to give o-hydroxy benzaldehyde involves the formation of

Question

Reaction of phenol with chloroform/sodium hydroxide to give o-hydroxy benzaldehyde involves the formation of (A) Chlorine molecules (B) Trichloro carbene (C) Chlorine atoms (D) Dichloro carbene

Tardigrade Admin · Accepted Answer

This is Reimer-Tiemann reaction where the electrophile is dichlorocarbene (: CCl2) generated from chloroform by the action of a base -OH+CHCl3 leftharpoons HOH+:CCl-3 → Cl-+: CCl2

Q. Reaction of phenol with chloroform/sodium hydroxide to give o-hydroxy benzaldehyde involves the formation of

Chlorine molecules

Trichloro carbene

Chlorine atoms

Dichloro carbene

This is Reimer-Tiemann reaction where the electrophile is dichlorocarbene $(: CC l_{2})$ generated from chloroform by the action of a base
$^{-} O H + C H C l_{3} ⇌ H O H + : CC l_{3}^{-} \to Cl - + : CC l_{2}$

Q. Reaction of phenol with chloroform/sodium hydroxide to give o-hydroxy benzaldehyde involves the formation of

Chlorine molecules

Trichloro carbene

Chlorine atoms

Dichloro carbene

This is Reimer-Tiemann reaction where the electrophile is dichlorocarbene (:CCl2​) generated from chloroform by the action of a base −OH+CHCl3​⇌HOH+:CCl3−​→Cl−+:CCl2​

This is Reimer-Tiemann reaction where the electrophile is dichlorocarbene $(: CC l_{2})$ generated from chloroform by the action of a base
$^{-} O H + C H C l_{3} ⇌ H O H + : CC l_{3}^{-} \to Cl - + : CC l_{2}$