Reaction of Br 2 with Na 2 CO 3 in aqueous solution gives sodium bromide and sodium bromate with evolution of CO 2 gas. The number of sodium bromide molecules involved in the balanced chemical equation is

Question

Reaction of Br 2 with Na 2 CO 3 in aqueous solution gives sodium bromide and sodium bromate with evolution of CO 2 gas. The number of sodium bromide molecules involved in the balanced chemical equation is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

3 Br 2+3 Na 2 CO 3 longrightarrow 5 NaBr + NaBrO 3+3 CO 2 So, number of NaBr molecules =5

Q. Reaction of $B r_{2}$ with $N a_{2} C O_{3}$ in aqueous solution gives sodium bromide and sodium bromate with evolution of $C O_{2}$ gas. The number of sodium bromide molecules involved in the balanced chemical equation is

$3 B r_{2} + 3 N a_{2} C O_{3} ⟶ 5 N a B r + N a B r O_{3} + 3 C O_{2}$
So, number of NaBr molecules $= 5$

Q. Reaction of Br2​ with Na2​CO3​ in aqueous solution gives sodium bromide and sodium bromate with evolution of CO2​ gas. The number of sodium bromide molecules involved in the balanced chemical equation is

3Br2​+3Na2​CO3​⟶5NaBr+NaBrO3​+3CO2​ So, number of NaBr molecules =5

Q. Reaction of $B r_{2}$ with $N a_{2} C O_{3}$ in aqueous solution gives sodium bromide and sodium bromate with evolution of $C O_{2}$ gas. The number of sodium bromide molecules involved in the balanced chemical equation is

$3 B r_{2} + 3 N a_{2} C O_{3} ⟶ 5 N a B r + N a B r O_{3} + 3 C O_{2}$
So, number of NaBr molecules $= 5$