Reaction of a carbonyl compound with dilute NaOH gives 4- methylpent -3- en -2- one. The carbonyl compound is:

Question

Reaction of a carbonyl compound with dilute NaOH gives 4- methylpent -3- en -2- one. The carbonyl compound is: (A) Acetaldehyde (B) Acetone (C) Formaldehyde (D) Propanal

Tardigrade Admin · Accepted Answer

The structure of the final product is Solution

The compound is an α ,β - unsaturated ketone. Such type of products is formed by the aldol condensation reaction. Among the given reagents, acetone can give the given final product on reactions with dilute NaOH . Solution

Q. Reaction of a carbonyl compound with dilute $N a O H$ gives $4 -$ methylpent $- 3 -$ en $- 2 -$ one. The carbonyl compound is:

Acetaldehyde

Acetone

Formaldehyde

Propanal

The structure of the final product is

The compound is an $α, β -$ unsaturated ketone. Such type of products is formed by the aldol condensation reaction. Among the given reagents, acetone can give the given final product on reactions with dilute $N a O H$ .

Q. Reaction of a carbonyl compound with dilute NaOH gives 4− methylpent −3− en −2− one. The carbonyl compound is: