Tardigrade
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Tardigrade
Question
Chemistry
Reaction CH 3 CONH 2 stackrel NaOBr longrightarrow gives:
Q. Reaction
C
H
3
CON
H
2
⟶
N
a
OB
r
gives:
1249
200
Amines
Report Error
A
C
H
3
B
r
12%
B
C
H
4
5%
C
C
H
3
OB
r
10%
D
C
H
3
N
H
2
73%
Solution:
This is a Hofmann bromamide reaction. The product is a primary amine with one carbon less.
C
H
3
CON
H
2
⟶
N
a
OB
r
C
H
3
N
H
2