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Tardigrade
Question
Chemistry
Ratio of O 2 and N 2 in the air is 1: 4. Find out the ratio of their solubilities in terms of mole fractions of O 2 and N 2 dissolved in water at atmospheric pressure and room temperature. [ K H ( O 2)=3.30 × 107 text torr K H ( N 2)=6.60 × 107 text torr ]
Q. Ratio of
O
2
and
N
2
in the air is
1
:
4
. Find out the ratio of their solubilities in terms of mole fractions of
O
2
and
N
2
dissolved in water at atmospheric pressure and room temperature.
[
K
H
(
O
2
)
=
3.30
×
1
0
7
torr
K
H
(
N
2
)
=
6.60
×
1
0
7
torr
]
1148
160
Solutions
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A
1
:
2
70%
B
2
:
1
21%
C
1
:
1
6%
D
None of these
3%
Solution:
p
O
2
=
5
1
×
1
=
0.2
ba
r
p
N
2
=
5
4
×
1
=
0.8
ba
r
p
=
K
H
x
(from Henry's law)
∴
x
N
2
x
O
2
=
K
H
(
O
2
)
p
O
2
×
p
N
2
K
(
H
)
(
N
2
)
=
0.8
×
3.30
×
1
0
7
0.2
×
6.60
×
1
0
7
=
2
1
x
O
2
:
x
N
2
=
1
:
2