Question

Range of the function $f(x)=\sqrt{4-x^2}$ is

• A. $(0,2)$
• B. $\{0,2\}$
• C. $[0,2]$
• D. $[0,2)$

Answer 1

Answer: (C)

$4-x^2\ge 0,x^2-4\le 0,x\in [-2,2]$ is domain
$\therefore$ Range $=[0,2]$