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  4. Range of the function f(x)=√4-x2 is

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Q. Range of the function $f(x)=\sqrt{4-x^{2}}$ is

Solution:

$4-x^{2} \geq 0, x^{2}-4 \leq 0, x \in[-2,2]$ is domain
$\therefore $ Range $=[0,2]$