R-2- chloropentane arrow Cl2hv Monochlorination takes place. Find the value of x , where x is the total number of products obtained.

Question

R-2- chloropentane arrow Cl2hv Monochlorination takes place. Find the value of x , where x is the total number of products obtained. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-xajdgkbyq2ekwntr.jpg" /> The configuration at carbon-2 is fixed, hence, substitution at carbon-1, carbon-2, and carbon-5 give single dichloro products. But substitution at carbon-2 and carbon-3 give a mixture of dichloro products. Total 7 products are formed.

Q. $R - 2 -$ chloropentane $\to_{C l_{2}}^{h v}$ Monochlorination takes place. Find the value of $x$ , where $x$ is the total number of products obtained.

The configuration at carbon-2 is fixed, hence, substitution at carbon-1, carbon-2, and carbon-5 give single dichloro products. But substitution at carbon-2 and carbon-3 give a mixture of dichloro products.
Total $7$ products are formed.

Q. R−2− chloropentane →Cl2​hv​ Monochlorination takes place. Find the value of x , where x is the total number of products obtained.

The configuration at carbon-2 is fixed, hence, substitution at carbon-1, carbon-2, and carbon-5 give single dichloro products. But substitution at carbon-2 and carbon-3 give a mixture of dichloro products. Total 7 products are formed.

Q. $R - 2 -$ chloropentane $\to_{C l_{2}}^{h v}$ Monochlorination takes place. Find the value of $x$ , where $x$ is the total number of products obtained.

The configuration at carbon-2 is fixed, hence, substitution at carbon-1, carbon-2, and carbon-5 give single dichloro products. But substitution at carbon-2 and carbon-3 give a mixture of dichloro products.
Total $7$ products are formed.