Quality factor of a series LCR circuit decreases from 3 to 2. Resonant frequency is 600 Hz. Change in band width is

Question

Quality factor of a series LCR circuit decreases from 3 to 2. Resonant frequency is 600 Hz. Change in band width is (A) zero (B) 100 Hz increase (C) 100 Hz decrease (D) 300 Hz increase

Tardigrade Admin · Accepted Answer

Relation between bandwidth and quality factor of series

L CR

circuit for a given resonant frequency,

Δ υ = \frac{υ _{0}}{Q}

υ_{0} = 600 Hz

For

Q = 3, Δ υ = \frac{600}{3} = 200 Hz

For

Q = 2, Δ υ = \frac{600}{3} = 300 Hz

Q. Quality factor of a series LCR circuit decreases from 3 to 2. Resonant frequency is 600Hz. Change in band width is

zero

100 Hz increase

100 Hz decrease

300 Hz increase

Relation between bandwidth and quality factor of series LCR circuit for a given resonant frequency, Δυ=Qυ0​​ υ0​=600Hz For Q=3,Δυ=3600​=200Hz For Q=2,Δυ=3600​=300Hz

Q. Quality factor of a series $L CR$ circuit decreases from 3 to 2. Resonant frequency is $600 Hz$ . Change in band width is

Relation between bandwidth and quality factor of series $L CR$ circuit for a given resonant frequency,
$Δ υ = \frac{υ _{0}}{Q}$
$υ_{0} = 600 Hz$
For $Q = 3, Δ υ = \frac{600}{3} = 200 Hz$
For $Q = 2, Δ υ = \frac{600}{3} = 300 Hz$