Proton is nearly 1836 times more massive than the electron. The Coulomb force of repulsion between two protons separated by a finite distance is F. The electrostátic force between two electrons separated by the same distance is

Question

Proton is nearly 1836 times more massive than the electron. The Coulomb force of repulsion between two protons separated by a finite distance is F. The electrostátic force between two electrons separated by the same distance is (A) F (B) (F/1837) (C) 1837 F (D) (1837/4) F

Tardigrade Admin · Accepted Answer

Force between protons F=(K(+e)(+e)/r2) Force between electrons F prime=(K(-e)(-e)/r2)=(K e2/r2) ⇒ F prime=F

Q. Proton is nearly $1836$ times more massive than the electron. The Coulomb force of repulsion between two protons separated by a finite distance is $F$ . The electrostátic force between two electrons separated by the same distance is

$F$

$\frac{F}{1837}$

$1837 F$

$\frac{1837}{4} F$

Force between protons $F = \frac{K ( + e ) ( + e )}{r ^{2}}$
Force between electrons $F^{'} = \frac{K ( - e ) ( - e )}{r ^{2}} = \frac{K e ^{2}}{r ^{2}}$
$\Rightarrow F^{'} = F$

Q. Proton is nearly 1836 times more massive than the electron. The Coulomb force of repulsion between two protons separated by a finite distance is F. The electrostátic force between two electrons separated by the same distance is

F

1837F​

1837F

41837​F

Force between protons F=r2K(+e)(+e)​ Force between electrons F′=r2K(−e)(−e)​=r2Ke2​ ⇒F′=F

Q. Proton is nearly $1836$ times more massive than the electron. The Coulomb force of repulsion between two protons separated by a finite distance is $F$ . The electrostátic force between two electrons separated by the same distance is

$F$

$\frac{F}{1837}$

$1837 F$

$\frac{1837}{4} F$

Force between protons $F = \frac{K ( + e ) ( + e )}{r ^{2}}$
Force between electrons $F^{'} = \frac{K ( - e ) ( - e )}{r ^{2}} = \frac{K e ^{2}}{r ^{2}}$
$\Rightarrow F^{'} = F$