Propene on treatment with chlorine at 500-600°C gives the following product (s):

Question

Propene on treatment with chlorine at 500-600°C gives the following product (s): (A) CH3-CH=CH-Cl (B) CH3- underset overset|ClC= CH2 (C) Cl-CH2-CH=CH2 (D) All the above

Tardigrade Admin · Accepted Answer

Propene on treatment with chlorine at 500-600°C produces allyl chloride. The reaction takes place as follows: CH3-CH =CH2 xrightarrow[500-600°]Cl2CH2Cl-CH=CH2 Allyl chloride (80 %) yield

Q. Propene on treatment with chlorine at $500 - 60 0^{\circ} C$ gives the following product (s):

$C H_{3} - C H = C H - Cl$

$C H_{3} - C ∣ l C = C H_{2}$

$Cl - C H_{2} - C H = C H_{2}$

All the above

Propene on treatment with chlorine at $500 - 60 0^{\circ} C$ produces allyl chloride. The reaction takes place as follows:
$C H_{3} - C H = C H_{2} C l_{2} 500 - 60 0^{\circ} C H_{2} Cl - C H = C H_{2}$
Allyl chloride $(80%)$ yield

Q. Propene on treatment with chlorine at 500−600∘C gives the following product (s):

CH3​−CH=CH−Cl

CH3​−C∣lC​=CH2​

Cl−CH2​−CH=CH2​