Question

Propene on treatment with chlorine at $500-600^{\circ}C$ gives the following product (s):

• A. $CH_3-CH=CH-Cl$
• B. $CH_3-\underset{\overset{|}{C}l}{C}= CH_2$
• C. $Cl-CH_2-CH=CH_2$
• D. All the above

Answer 1

Answer: (C)

Propene on treatment with chlorine at $500-600^{\circ}C$ produces allyl chloride. The reaction takes place as follows:
$CH_3-CH =CH_2 \xrightarrow[500-600^{\circ}]{Cl_2}CH_2Cl-CH=CH_2$
Allyl chloride $(80\%)$ yield