Question

Propene on reaction with each of the reagents given in column I gives products given in column II. Match the column and select the correct answer using the code given below:

Column I		Column II
(A)	$KMn{O}_4/H^{+}$	(1)	Propan-2-ol
(B)	$KMn{O}_4/O{H}^{-}$	(2)	Propan 1, 2,diol
(C)	$H_{2}O/H^{+}$	(3)	Acetic acid and $C{O}_2$
(D)	$O_3/Zn+H_{2}O$	(4)	Acetaldehyde + formaldehyde

• A. (A)-(4), (B)-(3), (C)-(2), (D)-(1)
• B. (A)-(3), (B)-(2), (C)-(1), (D)-(4)
• C. (A)-(3), (B)-(1), (C)-(2), (D)-(4)
• D. (A)-(3), (B)-(2), (C)-(4), (D)-(1)

Answer 1

Answer: (B)

(a) $\underset{\text{propene}}{C{H}_{3}CH}=C{H}_{2}C{H}_2\underset{\text{(Oxidation)}}{\overset{KMn{O}_4/H^{+}}{\to }}\underset{\text{Acetic acid}}{C{H}_{3}COOH}+C{O}_2$

(b) $\underset{\text{propene}}{C{H}_{3}CH}=C{H}_{2}C{H}_2\underset{\text{(Hydroxylation)}}{\overset{KMn{O}_4/H^{-}}{\to }}\underset{\text{propane- 1, 2-diol}}{C{H}_{3}COOH}-C{H}_{2}OH$

(c) $\underset{\text{propene}}{C{H}_{3}CH}=C{H}_{2}C{H}_2\underset{\text{(Mark.addition)}}{\overset{H_O/H^{+}}{\to }}\underset{\text{propan-2-ol}}{C{H}_{3}CHOH}-C{H}_3$

(d) $\underset{\text{Propene}}{C{H}_{3}CH=C{H}_2}\underset{(ii)Zn+H_{2}O\text{(Reductive ozonolysis)}}{\overset{(i)O_3}{\to }}$

$\underset{\text{Acetaldehyde}}{C{H}_3-CHO}+\underset{\text{Formaldehyde}}{O=C{H}_2}$