Tardigrade
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Tardigrade
Question
Chemistry
Pressure exerted by a perfect gas is equal to
Q. Pressure exerted by a perfect gas is equal to
1356
223
States of Matter
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A
Mean kinetic energy per unit volume
B
Half of the mean kinetic energy per unit volume
C
Two thirds of mean kinetic energy per unit volume
D
One third of mean kinetic energy per unit volume
Solution:
According to kinetic theory of gases,
C
=
M
3
RT
;
C
=
Root mean square velocity
or,
C
2
=
M
3
RT
or,
3
C
2
=
M
RT
=
W
P
V
[
∴
P
V
=
n
RT
]
or,
P
=
3
V
w
×
C
2
=
3
V
2
(
2
1
w
C
2
)
or,
P
=
3
2
of mean kinetic energy per unit volume.