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Q.
Pressure exerted by a perfect gas is equal to
States of Matter
Solution:
According to kinetic theory of gases,
$C=\sqrt{\frac{3 R T}{M}} $;
$ C=$ Root mean square velocity
or, $C ^{2}=\frac{3 RT }{ M }$
or, $\frac{C^{2}}{3}=\frac{R T}{M}=\frac{P V}{W}$
$[\therefore P V=n R T]$
or, $P=\frac{w \times C^{2}}{3 V}=\frac{2}{3 V}\left(\frac{1}{2} w C^{2}\right)$
or, $P=\frac{2}{3}$ of mean kinetic energy per unit volume.