Predict the order of Δo for the following compounds: I. [Fe(H2O)6]2+ II. [Fe(CN)2(H2O)4] III. [Fe(CN)4(H2O)2]2-

Question

Predict the order of Δo for the following compounds: I. [Fe(H2O)6]2+ II. [Fe(CN)2(H2O)4] III. [Fe(CN)4(H2O)2]2- (A) Δo(I) < Δ o(II) < Δ o(III) (B) Δo(II) < Δ o(I) < Δ o(III) (C) Δo(III) < Δ o(II) < Δ o(I) (D) Δo(II) < Δ o(III) < Δ o(I)

Tardigrade Admin · Accepted Answer

The value of Δo for mixed ligands depends on the additive contributions of the ligand strengths. Since CN- has greater ligand strength than H2O, the strength increases as the number of CN- ions increases.

Q. Predict the order of $Δ_{o}$ for the following compounds:
$I . [F e (H_{2} O)_{6}]^{2 +} II . [F e (CN)_{2} (H_{2} O)_{4}]$
$III . [F e (CN)_{4} (H_{2} O)_{2}]^{2 -}$

$Δ_{o} (I) < Δ_{o} (II) < Δ_{o} (III)$

$Δ_{o} (II) < Δ_{o} (I) < Δ_{o} (III)$

$Δ_{o} (III) < Δ_{o} (II) < Δ_{o} (I)$

$Δ_{o} (II) < Δ_{o} (III) < Δ_{o} (I)$

The value of $Δ_{o}$ for mixed ligands depends on the additive contributions of the ligand strengths. Since $C N^{-}$ has greater ligand strength than $H_{2} O$ , the strength increases as the number of $C N^{-}$ ions increases.

Q. Predict the order of Δo​ for the following compounds: I.[Fe(H2​O)6​]2+II.[Fe(CN)2​(H2​O)4​] III.[Fe(CN)4​(H2​O)2​]2−

Δo​(I)<Δo​(II)<Δo​(III)

Δo​(II)<Δo​(I)<Δo​(III)

Δo​(III)<Δo​(II)<Δo​(I)

Δo​(II)<Δo​(III)<Δo​(I)