Potential energy of a bar magnet of magnetic moment m placed in a magnetic field of induction B such that, it makes an angle θ with the direction of B is

Question

Potential energy of a bar magnet of magnetic moment m placed in a magnetic field of induction B such that, it makes an angle θ with the direction of B is (A) m B cos θ (B) -m B cos θ (C) m B(1- cos θ) (D) m B(1+ cos θ)

Tardigrade Admin · Accepted Answer

Potential energy P E=-m B( cos θ2- cos θ1) When θ1=90° (position of zero PE), θ2=θ PE =-m B cos θ

Q. Potential energy of a bar magnet of magnetic moment $m$ placed in a magnetic field of induction $B$ such that, it makes an angle $θ$ with the direction of $B$ is

$m B cos θ$

$- m B cos θ$

$m B (1 - cos θ)$

$m B (1 + cos θ)$

Potential energy $PE = - m B (cos θ_{2} - cos θ_{1})$
When $θ_{1} = 9 0^{\circ}$ (position of zero PE), $θ_{2} = θ$
$PE = - m B cos θ$

Q. Potential energy of a bar magnet of magnetic moment m placed in a magnetic field of induction B such that, it makes an angle θ with the direction of B is

mBcosθ

−mBcosθ

mB(1−cosθ)

mB(1+cosθ)