Potential energy curve of a body of mass m = 2 kg is shown in the figure, it is released from rest at point A. Maximum distance covered by it on the positive x-axis till it momentarily comes to rest from the origin is

Question

Potential energy curve of a body of mass m = 2 kg is shown in the figure, it is released from rest at point A. Maximum distance covered by it on the positive x-axis till it momentarily comes to rest from the origin is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/e621a9be4cc4fdaab89080c5e9c77d71-.png" /> (A) 1 m (B) 2 m (C) (3/2) m (D) (1/2) m

Tardigrade Admin · Accepted Answer

From energy conservation U(x) = 16 J and (dU/dx) = 16 J/m Hence U = 16x ⇒ 16 = 16 x x = 1 m

Q. Potential energy curve of a body of mass $m = 2 k g$ is shown in the figure, it is released from rest at point A. Maximum distance covered by it on the positive x-axis till it momentarily comes to rest from the origin is

$1 m$

$2 m$

$\frac{3}{2} m$

$\frac{1}{2} m$

From energy conservation $U (x) = 16 J$
and $\frac{d U}{d x} = 16 J / m$
Hence $U = 16 x$
$\Rightarrow 16 = 16 x$
$x = 1 m$

Q. Potential energy curve of a body of mass m=2kg is shown in the figure, it is released from rest at point A. Maximum distance covered by it on the positive x-axis till it momentarily comes to rest from the origin is

1m

2m

23​m

21​m