Potential energy as a function of r is given by U =( A / r 10)-( B / r 5), where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be:

Question

Potential energy as a function of r is given by U =( A / r 10)-( B / r 5), where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be: (A) (( A / B ))(1/5) (B) ((B/A))(1/5) (C) ((2 A / B ))(1/5) (D) (( B /2 A ))(1/5)

Tardigrade Admin · Accepted Answer

(-10 A / r 11)+(5 B / r 6)=0 r 5=(10 A /5 B )=(2 A / B )

Q. Potential energy as a function of $r$ is given by $U = \frac{A}{r ^{10}} - \frac{B}{r ^{5}}$ , where $r$ is the interatomic distance, $A$ and $B$ are positive constants. The equilibrium distance between the two atoms will be:

$(\frac{A}{B})^{\frac{1}{5}}$

$(\frac{B}{A})^{\frac{1}{5}}$

$(\frac{2 A}{B})^{\frac{1}{5}}$

$(\frac{B}{2 A})^{\frac{1}{5}}$

$\frac{- 10 A}{r ^{11}} + \frac{5 B}{r ^{6}} = 0$
$r^{5} = \frac{10 A}{5 B} = \frac{2 A}{B}$

Q. Potential energy as a function of r is given by U=r10A​−r5B​, where r is the interatomic distance, A and B are positive constants. The equilibrium distance between the two atoms will be:

(BA​)51​

(AB​)51​

(B2A​)51​

(2AB​)51​