Potential difference between A and B in the following circuit

Question

Potential difference between A and B in the following circuit (A) 4 V (B) 5.6 V (C) 2.8 V (D) 6 V

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/c28b6cce311e537a907eb281a9c83901-.png" /> Apply Kirchhoff's second loop law, go from A to B anti-clockwise I(2+8) =6-4 I ⋅ 10 =2 I =0.2 A VA-I × 2+6 =VB VA-VB =0 ⋅ 2 × 2-6 =0.4-6=-5.6 V Hence, VA < VB and VB A=5.6 V

Q. Potential difference between $A$ and $B$ in the following circuit

4 V

5.6 V

2.8 V

6 V

Apply Kirchhoff's second loop law, go from $A$ to $B$ anti-clockwise
$I (2 + 8) = 6 - 4$
$I \cdot 10 = 2$
$I = 0.2 A$
$V_{A} - I \times 2 + 6 = V_{B}$
$V_{A} - V_{B} = 0 \cdot 2 \times 2 - 6$
$= 0.4 - 6 = - 5.6 V$
Hence, $V_{A} < V_{B}$
and $V_{B A} = 5.6 V$

Q. Potential difference between A and B in the following circuit

4 V

5.6 V

2.8 V

6 V

Apply Kirchhoff's second loop law, go from A to B anti-clockwise I(2+8)=6−4 I⋅10=2 I=0.2A VA​−I×2+6=VB​ VA​−VB​=0⋅2×2−6 =0.4−6=−5.6V Hence, VA​<VB​ and VBA​=5.6V

Q. Potential difference between $A$ and $B$ in the following circuit

Apply Kirchhoff's second loop law, go from $A$ to $B$ anti-clockwise
$I (2 + 8) = 6 - 4$
$I \cdot 10 = 2$
$I = 0.2 A$
$V_{A} - I \times 2 + 6 = V_{B}$
$V_{A} - V_{B} = 0 \cdot 2 \times 2 - 6$
$= 0.4 - 6 = - 5.6 V$
Hence, $V_{A} < V_{B}$
and $V_{B A} = 5.6 V$