Potential difference across AB in the network shown is

Question

Potential difference across AB in the network shown is (A) Zero (B) E (C) E-( operatornameIr/2) (D) E-2 I r

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5da7f1a241612af60457d5f1abf928a3-.png" /> i=(E/R) VA-E+i r-E+i r=VB VA-E+E-E+E=VB VA=VB

Q. Potential difference across $A B$ in the network shown is

Zero

$E$

$E - \frac{Ir}{2}$

$E - 2 I r$

$i = \frac{E}{R}$
$V_{A} - E + i r - E + i r = V_{B}$
$V_{A} - E + E - E + E = V_{B}$
$V_{A} = V_{B}$

Q. Potential difference across AB in the network shown is

Zero

E

E−2Ir​

E−2Ir

i=RE​ VA​−E+ir−E+ir=VB​ VA​−E+E−E+E=VB​ VA​=VB​

Q. Potential difference across $A B$ in the network shown is

$E$

$E - \frac{Ir}{2}$

$E - 2 I r$

$i = \frac{E}{R}$
$V_{A} - E + i r - E + i r = V_{B}$
$V_{A} - E + E - E + E = V_{B}$
$V_{A} = V_{B}$