Question

Potassium chlorate is prepared by electrolysis of $KCl$ in basic solution as shown by following equation.
$6O{H}^{-}+C{l}^{-}\to Cl{O}_3^{-}+3H_{2}O+6e^{-}$
A current of $x$ A has to be passed for $10h$ to produce $10.0g$ of potassium chlorate. the value of $x$ is_________(Nearest integer)
(Molar mass of $KCl{O}_3=122.6gmo{l}^{-1},F=96500C$ )

Answer 1

Answer: 1

$W=\frac{E}{F}\times I\times t$
$10=\frac{122.6}{96500\times 6}\times x\times 10\times 3600$
$X=1.311$