Q.
Point charge q1=2μC and q2=−1μC are kept at points x=0 and x=6, respectively. Electrical potential will be zero at points
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Electrostatic Potential and Capacitance
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Solution:
Potential will be zero at two points.
At internal point (M), 4πε01×[(6−l)2×10−6+l(−1×10−6)]=0 ⇒l=2
So distance of M from origin, x=6−2=4
At exterior point (N), 4πε01×[(6+l′)2×10−6+l′(−1×10−6)]=0 ⇒l′=6
So distance of N from origin, x=6+6=12