Plutonium decays with a half-life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is:

Question

Plutonium decays with a half-life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is: (A)  (1/2)  (B)  (1/3)  (C)  (1/4)  (D)  (1/8)

Tardigrade Admin · Accepted Answer

No. of half - lives n n=(t/T)=(72000/24000)=3 From relation, (N/N0)=( (1/2) )n=( (1/2) )3=(1/8)

Q. Plutonium decays with a half-life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is:

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{1}{4}$

$\frac{1}{8}$

No. of half - lives n $n = \frac{t}{T} = \frac{72000}{24000} = 3$ From relation, $\frac{N}{N _{0}} = (\frac{1}{2})^{n} = (\frac{1}{2})^{3} = \frac{1}{8}$