Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Plutonium decays with a half-life of 24000 years. If plutonium is stored for 72000 years, the fraction of it that remains is:

EAMCETEAMCET 1998

Solution:

No. of half - lives n $ n=\frac{t}{T}=\frac{72000}{24000}=3 $ From relation, $ \frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}={{\left( \frac{1}{2} \right)}^{3}}=\frac{1}{8} $