Planck's constant 6.6× 10- 27erg- second, velocity of light =3× 1010cm/s , the energy of photon of wave-length 3000 mathringA will be :

Question

Planck's constant 6.6× 10- 27erg- second, velocity of light =3× 1010cm/s , the energy of photon of wave-length 3000 mathringA will be : (A) 6.6× 10- 12erg (B) 13.2× 10- 12erg (C) 3.3× 10- 12erg (D) 6.6× 10- 19erg

Tardigrade Admin · Accepted Answer

E=(hc/λ ) =(6 . 6 × 10- 27 × 3 × 1010/3000 × 10- 8)=6.6× 10- 12erg

Q. Planck's constant $6.6 \times 1 0^{- 27} er g -$ second, velocity of light $= 3 \times 1 0^{10} c m / s$ , the energy of photon of wave-length $3000 \overset{˚}{A}$ will be :

$6.6 \times 1 0^{- 12} er g$

$13.2 \times 1 0^{- 12} er g$

$3.3 \times 1 0^{- 12} er g$

$6.6 \times 1 0^{- 19} er g$

$E = \frac{h c}{λ}$
$= \frac{6.6 \times 1 0 ^{- 27} \times 3 \times 1 0 ^{10}}{3000 \times 1 0 ^{- 8}} = 6.6 \times 1 0^{- 12} er g$

Q. Planck's constant 6.6×10−27erg− second, velocity of light =3×1010cm/s , the energy of photon of wave-length 3000A˚ will be :

6.6×10−12erg

13.2×10−12erg

3.3×10−12erg

6.6×10−19erg