pKa of a weak acid (HA) and pKb of a weak base (BOH) are 3.2 and 3.4, respectively. .The pH of their salt (AB) solution is :

Question

pKa of a weak acid (HA) and pKb of a weak base (BOH) are 3.2 and 3.4, respectively. .The pH of their salt (AB) solution is : (A) 7.0 (B) 1.0 (C) 7.2 (D) 6.9

Tardigrade Admin · Accepted Answer

pH=7+(1/2)(pKa-pKb) =7+(1/2)(3.2-3.4) =6.9

Q. $p K_{a}$ of a weak acid (HA) and $p K_{b}$ of a weak base (BOH) are $3.2$ and $3.4,$ respectively. .The pH of their salt (AB) solution is :

7.0

1.0

7.2

6.9

$p H = 7 + \frac{1}{2} (p K_{a} - p K_{b})$

$= 7 + \frac{1}{2} (3.2 - 3.4)$

$= 6.9$

Q. pKa​ of a weak acid (HA) and pKb​ of a weak base (BOH) are 3.2 and 3.4, respectively. .The pH of their salt (AB) solution is :

7.0

1.0

7.2

6.9

pH=7+21​(pKa​−pKb​) =7+21​(3.2−3.4) =6.9

Q. $p K_{a}$ of a weak acid (HA) and $p K_{b}$ of a weak base (BOH) are $3.2$ and $3.4,$ respectively. .The pH of their salt (AB) solution is :

$p H = 7 + \frac{1}{2} (p K_{a} - p K_{b})$

$= 7 + \frac{1}{2} (3.2 - 3.4)$

$= 6.9$