Phosphorus cannot form PH5 with its outer electronic configuration as 3s23p3 because

Question

Phosphorus cannot form PH5 with its outer electronic configuration as 3s23p3 because (A) phosphorus cannot show +5 oxidation state (B) PH5 is not a stable compound (C) ΔaH value of dihydrogen and ΔegH value of hydrogen do not favour higher oxidation state of phosphorus (D) phosphorus is not very reactive hence does not form PH5

Tardigrade Admin · Accepted Answer

Since higher oxidation state of P is not favoured by high ΔaH of dihydrogen and ΔegH of hydrogen, P does not form PH5 though it exhibits +3 and +5 oxidation states.

Q. Phosphorus cannot form $P H_{5}$ with its outer electronic configuration as $3 s^{2} 3 p^{3}$ because

phosphorus cannot show $+ 5$ oxidation state

$P H_{5}$ is not a stable compound

$Δ_{a} H$ value of dihydrogen and $Δ_{e g} H$ value of hydrogen do not favour higher oxidation state of phosphorus

phosphorus is not very reactive hence does not form $P H_{5}$

Since higher oxidation state of $P$ is not favoured by high $Δ_{a} H$ of dihydrogen and $Δ_{e g} H$ of hydrogen, $P$ does not form $P H_{5}$ though it exhibits $+ 3$ and $+ 5$ oxidation states.

Q. Phosphorus cannot form PH5​ with its outer electronic configuration as 3s23p3 because

phosphorus cannot show +5 oxidation state

PH5​ is not a stable compound

Δa​H value of dihydrogen and Δeg​H value of hydrogen do not favour higher oxidation state of phosphorus

phosphorus is not very reactive hence does not form PH5​