Phenol dimerises in benzene having vant Hoff factor 0.54. What is the degree of association ?

Question

Phenol dimerises in benzene having vant Hoff factor 0.54. What is the degree of association ? (A) 0.46 (B) 0.54 (C) 0.27 (D) 0.92

Tardigrade Admin · Accepted Answer

2 C 6 H 5 OH leftharpoons( C 6 H 5 OH )2 Before association 1 0 After association 1- α α / 2 Total =1-α+(α/2)=1-α / 2 i=1-α / 2 or α / 2=1-i=1-0.54=0.46 or α=0.92

Q. Phenol dimerises in benzene having vant Hoff factor 0.54. What is the degree of association ?

0.46

0.54

0.27

0.92

$2 C_{6} H_{5} O H ⇌ (C_{6} H_{5} O H)_{2}$
Before association $10$
After association 1- $αα /2$
Total $= 1 - α + \frac{α}{2} = 1 - α /2$
$i = 1 - α /2$
or $α /2 = 1 - i = 1 - 0.54 = 0.46$
or $α = 0.92$

Q. Phenol dimerises in benzene having vant Hoff factor 0.54. What is the degree of association ?

0.46

0.54

0.27

0.92

2C6​H5​OH⇌(C6​H5​OH)2​ Before association 10 After association 1- αα/2 Total =1−α+2α​=1−α/2 i=1−α/2 or α/2=1−i=1−0.54=0.46 or α=0.92

$2 C_{6} H_{5} O H ⇌ (C_{6} H_{5} O H)_{2}$
Before association $10$
After association 1- $αα /2$
Total $= 1 - α + \frac{α}{2} = 1 - α /2$
$i = 1 - α /2$
or $α /2 = 1 - i = 1 - 0.54 = 0.46$
or $α = 0.92$