Tardigrade
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Tardigrade
Question
Chemistry
Ph - C ≡ C- CH3 xrightarrow[H+]Hg2+ A;A is
Q.
P
h
−
C
≡
C
−
C
H
3
H
g
2
+
H
+
A
;
A
is
1875
245
IIT JEE
IIT JEE 2003
Hydrocarbons
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A
28%
B
24%
C
34%
D
13%
Solution:
Reaction proceeds through carbocation intermediate :