Percentage of Se (atomic mass = 78.4) in peroxidase anhydrase enzyme is 0.5% by mass, then minimum molecular mass of peroxidase anhydrase enzyme is:

Question

Percentage of Se (atomic mass = 78.4) in peroxidase anhydrase enzyme is 0.5% by mass, then minimum molecular mass of peroxidase anhydrase enzyme is: (A) 1.576 × 104 (B) 1.576 × 103 (C) 15.76 (D) 2.136 × 104

Tardigrade Admin · Accepted Answer

The enzyme must contain at least one atom of Se ∵ 0.5 g enzyme, molar mass = 100 ∴ 78.4 g enzyme, molar mass =(100× 78.4/0.5) =1.576 × 104

Q. Percentage of Se (atomic mass = 78.4) in peroxidase anhydrase enzyme is 0.5% by mass, then minimum molecular mass of peroxidase anhydrase enzyme is:

$1.576 \times 1 0^{4}$

$1.576 \times 1 0^{3}$

$15.76$

$2.136 \times 1 0^{4}$

The enzyme must contain at least one atom of Se
$∵ 0.5 g$ enzyme, molar mass = 100
$∴ 78.4 g$ enzyme, molar mass $= \frac{100 \times 78.4}{0.5}$
$= 1.576 \times 1 0^{4}$

Q. Percentage of Se (atomic mass = 78.4) in peroxidase anhydrase enzyme is 0.5% by mass, then minimum molecular mass of peroxidase anhydrase enzyme is:

1.576×104

1.576×103

15.76

2.136×104

The enzyme must contain at least one atom of Se ∵0.5g enzyme, molar mass = 100 ∴78.4g enzyme, molar mass =0.5100×78.4​ =1.576×104

$1.576 \times 1 0^{4}$

$1.576 \times 1 0^{3}$

$15.76$

$2.136 \times 1 0^{4}$

The enzyme must contain at least one atom of Se
$∵ 0.5 g$ enzyme, molar mass = 100
$∴ 78.4 g$ enzyme, molar mass $= \frac{100 \times 78.4}{0.5}$
$= 1.576 \times 1 0^{4}$