Question

PCl₅ causes cleavage of ether linkage $\text{R}-\text{O}-{\text{R}}^{{}^{\prime }}$ forming RCl, R'Cl and POCl₃.

C₅H₁₂O on reaction with PCl₅ forms 2-chloropropane and 1-chloroethane as main compounds.

Thus, C₅H₁₂O is named as

• A. 1-ethoxypropane
• B. 2-ethoxypropane
• C. 1-ethylpropane
• D. 2-ethylpropane

Answer 1

Answer: (B)

$\text{R}-\text{O}-{\text{R}}^{{}^{\prime }}\stackrel{{\text{PCl}}_5}{\to }\text{R}-\text{Cl}+{\text{R}}^{{}^{\prime }}\text{Cl}+{\text{POCl}}_3$



O is replaced by two Cl-atoms one each on alkly group.

Thus, C₅H₁₂O is