PCl 5 is 50 % dissociated at 20° C and 1 atm pressure. The value of Kp is

Question

PCl 5 is 50 % dissociated at 20° C and 1 atm pressure. The value of Kp is (A) 0.444 (B) 0.555 (C) 0.333 (D) 0.666

Tardigrade Admin · Accepted Answer

Let there be 1 mole of PCl 5 initially Number of moles dissociated (1 × 50/100)=0.5 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1e056bbe695800dfcae3af13a7df28e8-.png" /> P PCl 5=(0.5/1.5) × 1 ; P PCl 3=(0.5/1.5) × 1= P Cl 2 K P =( P pcl 3 P cl 2/ P pcl 5) =((0.5 / 1.5)(0.5 / 1.5)/(0.5 / 1.5)) =0.333

Q. PCl5​ is 50% dissociated at 20∘C and 1atm pressure. The value of Kp​ is

0.444

0.555

0.333

0.666

Let there be 1 mole of PCl5​ initially Number of moles dissociated 1001×50​=0.5 PPCl5​​=1.50.5​×1;PPCl3​​=1.50.5​×1=PCl2​​ KP​=Ppcl5​​Ppcl3​​Pcl2​​​ =(0.5/1.5)(0.5/1.5)(0.5/1.5)​ =0.333

Q. $PC l_{5}$ is $50%$ dissociated at $2 0^{\circ} C$ and $1 a t m$ pressure. The value of $K_{p}$ is