Question

$Pb{O}_2$ is obtained from

• A. the reaction of $PbO$ with $HCl$
• B. thermal decomposition of $Pb(N{O}_3{)}_2$ at $200^{\circ }C$
• C. the reaction of $P{b}_3{O}_4$ with $HN{O}_3$
• D. the reaction of $Pb$ with air at room temperature

Answer 1

Answer: (C)

(a) $PbO+HCl\to \underset{\text{(not correct option) }}{PbC{l}_2+H_{2}O}$
(b) $2pb(N{O}_3{)}_2\to 2PbO+\underset{\text{(not correct option)}}{4N{O}_2+O_2}$
(c) $P{b}_3{O}_4+4HN{O}_3\to 2Pb(N{O}_3{)}_2+Pb{O}_2+2h_{2}O$ (correct option)
(d) Pb + air (contains $O_2,H_{2}O$ and $C{O}_2)$ $\underset{\text{temperature}}{\overset{\text{room}}{\to }}$
Protective layer of varying composition, mainly $PbC{O}_3$ is formed only on the surface,