Question

$Pb$ reacts with dilute $HN{O}_3$ produces :

• A. $NO$
• B. $N{H}_{4}N{O}_3$
• C. $N_2{O}_5$
• D. $N{O}_2$

Answer 1

Answer: (A)

$Pb$ reacts with dilute $HN{O}_3$ produces $NO$.
$3Pb+\underset{\text{dil.}}{8\mathrm{HNO}{}_3}$$\to$$3Pb(N{O}_3{)}_2+2NO+4H_{2}O$