Passage of electricity through dil H2SO4 for 1 hour liberates a total of 224ml of H2 at S.T.P. The magnitude of current would be :-

Question

Passage of electricity through dil H2SO4 for 1 hour liberates a total of 224ml of H2 at S.T.P. The magnitude of current would be :- (A) 0.27 amperes (B) 0.54 amperes (C) 0.042 amperes (D) 0.73 amperes

Tardigrade Admin · Accepted Answer

moles of hydrogen gas =(224/22400)=10- 2 geq to H2 (g)= textmole× n text factor =2× (10)- 2 geq=(i × t/96500) 2× 10- 2=(i × 3600/96500) i=0.536∼ eq0.54A

Q. Passage of electricity through dil $H_{2} S O_{4}$ for $1$ hour liberates a total of $224 m l$ of $H_{2}$ at $S . T . P .$ The magnitude of current would be :-

$0.27$ amperes

$0.54$ amperes

$0.042$ amperes

$0.73$ amperes

moles of hydrogen gas $= \frac{224}{22400} = 1 0^{- 2}$
$g_{e q}$ to $H_{2 (g)} = mole \times n factor = 2 \times (10)^{- 2}$
$g_{e q} = \frac{i \times t}{96500}$
$2 \times 1 0^{- 2} = \frac{i \times 3600}{96500}$
$i = 0.536 \sim e q 0.54 A$

Q. Passage of electricity through dil H2​SO4​ for 1 hour liberates a total of 224ml of H2​ at S.T.P. The magnitude of current would be :-

0.27 amperes

0.54 amperes

0.042 amperes

0.73 amperes