Q.
P,Q, and R are on AB,BC, and AC of the equilateral triangle ABC, respectively. AP:PB=CQ:QB=1 :
2. G is the centroid of the triangle PQB and R is the mid-point of AC. Find BG:GR.
Let AB=BC=AC=3x ∴BP=BQ=PQ=2x (∵AP:BP=CQ:BQ=1:2)
As △BPQ and △BAC are equilateral triangle, the centroid of △BPQ lies on BR (where BR is median drawn on to AC )
We know that centroid divides the median in the ratio 2:1. ∴BG=322[3(2x)]=323x
But BR=23(3x)=233x
Now GR=BR−BG =233x−323x=653x
Now BG:GR=323x:653x=4:5.