Question

Oxidation states of $X,Y,Z$ are $+2,+5$ and $-2$ respectively. The formula of the compound formed by these will be

• A. $X_{2}Y{Z}_6$
• B. $X{Y}_2{Z}_6$
• C. $X{Y}_5$
• D. $X_{3}Y{Z}_4$

Answer 1

Answer: (B)

We know that, the algebraic sum of the oxidation states is always zero in neutral compound.
Oxidation states of $X=+2$
$Y=+5$
$Z=-2$
So, the algebraic sum of total $X,Y$ and $Z$ should be equal to zero which is found in $X{Y}_2{Z}_6$.
$X{Y}_2{Z}_6=+2+(5\times 2)+(-2\times 6)$
$=+2+10-12=0$