Thank you for reporting, we will resolve it shortly
Q.
Oxidation states of $X, Y, Z$ are $+2,+5$ and $-2$ respectively. The formula of the compound formed by these will be
Redox Reactions
Solution:
We know that, the algebraic sum of the oxidation states is always zero in neutral compound.
Oxidation states of $X=+2$
$Y=+5$
$Z=-2$
So, the algebraic sum of total $X, Y$ and $Z$ should be equal to zero which is found in $X Y_{2} Z_{6}$.
$X Y_{2} Z_{6} =+2+(5 \times 2)+(-2 \times 6)$
$=+2+10-12=0$