Oxidation states of P in H4P2O5,H4P2O6,H4P2O7, are respectively

Question

Oxidation states of P in H4P2O5,H4P2O6,H4P2O7, are respectively (A) +3, +4, +5 (B) +3, +5, +4 (C) +5, +3, +4 (D) +5, +4, +3

Tardigrade Admin · Accepted Answer

The value of O.No. of P- atoms in these acids are as follows H4P2O5 arrow 4+2x-10=0 2x=+6 x=+3 H4P2O7 arrow 4+2x-12=0 x=+4 H4P2O7 arrow 4+2x-14=0 x=+5

Q. Oxidation states of P in $H_{4} P_{2} O_{5}, H_{4} P_{2} O_{6}, H_{4} P_{2} O_{7},$ are respectively

+3, +4, +5

+3, +5, +4

+5, +3, +4

+5, +4, +3

The value of O.No. of P- atoms in these acids are as follows
$H_{4} P_{2} O_{5} \to 4 + 2 x - 10 = 0$
$2 x = + 6$
$x = + 3$
$H_{4} P_{2} O_{7} \to 4 + 2 x - 12 = 0$
$x = + 4$
$H_{4} P_{2} O_{7} \to 4 + 2 x - 14 = 0$
$x = + 5$

Q. Oxidation states of P in H4​P2​O5​,H4​P2​O6​,H4​P2​O7​, are respectively