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Tardigrade
Question
Chemistry
Oxidation state of S in H2S2O8 is
Q. Oxidation state of
S
in
H
2
S
2
O
8
is
2565
185
Redox Reactions
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A
+
6
47%
B
+
7
40%
C
+
8
9%
D
0
4%
Solution:
H
2
S
2
O
8
Two oxygen atoms are involved in peroxide linkage, hence oxidation number will be
−
1
(each).