Question

Oxidation state of oxygen atom in potassium peroxide is

• A. zero
• B. $-1/2$
• C. $-1$
• D. $-2$

Answer 1

Answer: (C)

${\stackrel{+1}{K}}_2\stackrel{x}{O_2}$ i.e., $2(+1)+2(x)=0\Rightarrow x=-1$

Alternatively, oxidation number of oxygen in peroxides is $-1$.